06.11.2011, 18:05
[H3O+] = 100.000*[OH-]
[H3O+]*[OH-] = 10^-14
[OH-]*[OH-]*100.000 = 10^-14
[OH-]^2 = 10^-14/100.000
[OH-]^2 = 10^-19
[OH-] = 3,16*10^-10
pOH = -log (3,16*10^-10)
pOH = 9,5
pH = 4,5
[H3O+]*[OH-] = 10^-14
[OH-]*[OH-]*100.000 = 10^-14
[OH-]^2 = 10^-14/100.000
[OH-]^2 = 10^-19
[OH-] = 3,16*10^-10
pOH = -log (3,16*10^-10)
pOH = 9,5
pH = 4,5

